Still trying to spec my air compressors - investigating cubic feet of air

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To calculate the cubic feet of air a tire can hold, we need to make certain assumptions about the tire's overall dimensions and the shape of the air-filled space inside it. Here's a simplified approach based on the tire dimensions:

**Assumptions:**
- Tire size: 20x12.5 (which typically means 20 inches in diameter and 12.5 inches wide).
- Rim width: 9.5 inches wide.
- The inner air volume of the tire is approximately cylindrical.

**Steps to Estimate Volume:**
**Convert tire dimensions to feet**:
- Diameter: 20 inches = 20/12 = 1.67 feet.
- Width: 12.5 inches = 12.5/12 = 1.04 feet.

**Assume the rim subtracts from the internal volume**: The rim (9.5 inches wide) takes up space inside the tire. We'll assume the tire itself has a cross-sectional thickness and that the inner diameter is less than 20 inches due to the rim.

Let's assume the average diameter for the air space inside the tire is 18 inches (1.5 feet). This is a rough estimate that accounts for the space taken up by the rim and tire walls.

**Calculate the air volume inside the tire**: The formula for the volume of a cylinder is:

V=πr2hV = \pi r^2 hV=πr2h

Where:

- rrr is the radius of the tire’s inner air-filled area (1.5 feet / 2 = 0.75 feet).
- hhh is the tire's width (1.04 feet).

So, for this tire:

V=π×(0.75)2×1.04V = \pi \times (0.75)^2 \times 1.04V=π×(0.75)2×1.04 V≈3.14×0.5625×1.04V \approx 3.14 \times 0.5625 \times 1.04V≈3.14×0.5625×1.04 V≈1.84 cubic feetV \approx 1.84 \text{ cubic feet}V≈1.84 cubic feet

Thus, the estimated volume of air the tire can hold is approximately

**1.84 cubic feet**. This is a rough estimate, and the actual volume may vary depending on the tire’s exact shape and internal structure.