Is anyone curious what kind of kinetic recovery it would take to bust those 4 bolts off? I am, so I learned myself some math.
The minimum ultimate tensile strength of x4 M12x1.25 grade 8.8 bolts is 294,800N. F=m x a. So, to apply 294kN, a 2500kg Montero would need to accelerate at a rate of 118m/s^2.
Now lets apply this to a kinetic rope recovery. Let's take a 6.1 meter long kinetic rope, according to the manufacturer it will stretch 30% of its length or 1.83m. So in a recovery of a completely stuck and immovable object, the rope will decelerate the Montero from starting velocity to 0m/s in a distance of 1.83 meters.
Now we can find what starting velocity will result in an acceleration of 118m/s^2 over a distance of 1.83m
(starting velocity)^2 = (final velocity)^2 x 2(acceleration x distance)
(starting velocity)^2 = (0)^2 x 2(118 x 1.83)
starting velocity = 20.8 m/s or 46mph
TLDR, if you tried to perform a kinetic recovery on a brick wall, you would need to accelerate up to a speed of 46mph to apply 294,800N of force and break your 4 bolts off. This is just theoretical/hypothetical physics, use this information as you will.