Nope, not hurt one bit at all. There is not one thing there that discredits anything I have said regarding the voltage being higher at the charger terminals than at the load (battery), or that copper wiring has a voltage drop.
Instead it appears you may have misread that part of the page (which may have been oversimplified), and is where I think you've been thrown off. Read the part above right where that section begins (Kirchhoff's Voltage Law).
Kirchhoff's Law simply states that the
total sum of voltages in a circuit (loop) is zero (total drops = EMF). If we have a PV panel creating 17 volts like you used for your example, and the battery is at 14.0 volts, the wire from panel to battery has a 1.5V potential (loss or drop, in layman's terms), the wire back to the panel also has 1.5V. The sum of all that would be 0:
1.5 + 14.0 + 1.5V - 17.0 = 0
But now lets look at what happens when a PWM charge controller is inserted into the loop as you say (lets say that the controller is located midway between the panel and the battery):
Now we have broken the 2 wires into 2 sections each, each with a 0.75V drop (2 wires on the panel to controller side, 2 from controller to battery). So now the loop goes like:
0.75 + 0.75 + 14.0 + 0.75 + 0.75 - 17.0 = 0.
Remembering that the controller is only capable of measuring voltage at the point of the circuit that is it's output terminal, it sees the 14.0V of the battery, plus 0.75V + 0.75V = 15.5V. That 15.5V quite obviously would make the controller curtail it's current output very quickly.
So now that the controller has cut the output down to 14.4V (entered Absorb mode), the controller has now "broken" the loop between the battery and the PV panel. Now we have 2 separate "loops" not unlike like you say there would be on a MPPT unit. This means the controller has now limited the EMF to 14.4V within the "loop" that is the controller and the battery.
So now we have the following:
0.2V + 14.0V + 0.2V - 14.4V = 0
Lets say the system has a 10-amp capacity and that each wire has 0.075 ohms resistance.
0.075 ohms at 0.2V (×2 wires) will only allow 2.666 amps to flow to the battery (0.2V ÷ 0.075Ω = 2.666~A). This means the system at this point is operating at barely over ¼ capacity while trying to bring that battery up to the full 14.4V that otherwise would've been the Bulk stage's job (and only gets to be less & less as the battery's voltage rises. In theory, the battery can
never actually reach 14.4V).
With such quantity of resistance in the wiring, a 10-amp system controller would actually quit the Bulk stage with the battery at 12.9V. (0.75V + 12.9V + 0.75V - 14.4V = 0)(10A × 0.075Ω = 0.75V). I certainly would call that a pretty significant degradation in charging performance, if you ask me...
So lets shorten up the wiring and get that resistance down to something more reasonable, like 0.005 ohms (about what 5 feet of #10 AWG would be). At 10 amps, 0.005 ohms has a potential of 0.05V.
Now we're looking at something more like the battery reaching 14.3V before the controller decides to quit Bulk:
0.05V + 14.30V + 0.05V - 14.4V = 0
That's certainly a hell of a lot better than it quitting with the battery at 12.9V...
The Absorb stage now can do what it's supposed to: allow the battery to absorb energy and bring it to full charge in the quickest time possible without excessive gassing.
Now... Can we put this issue to rest?
I must be missing something, because I don't see that.
Page 19, Step 1.
