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Which brings me full circle back to my original question: How many amps can I pull through a factory 12v power outlet safely?
Depends on who made the parts and what the various parts are rated at. You might have a receptacle rated 15a with a plug plugged into it rated at 10a, feeding #12 wire rated at 20a.
The weakest part is the limit. So in that example, 10a.
IIRC the 12v outlet on my 4runner had a 15a fuse and the one I put on my Suburban I also put a 15a fuse on.
I just added a twin power receptacle. It came with #12 wire. I spliced that to #10 (had some laying around) and ran it back to the fuse block and a 20a fuse. Is each individual socket good for 20a? I doubt it. But I won't be plugging 20a of load into either socket. 2 10a loads is more likely.
But theoretically I could overload the individual sockets, which are probably rated for 15a each because the fuse that protects the whole thing is 20a.
What determines the amperage of the current drawn by the depleted battery?
The total resistance of the wiring and battery vs. the supply voltage potential.
Higher wiring/battery resistance, or lower source potential - less amps flow.
Lower wiring/battery resistance, or higher source potential - more amps flow.
Assuming the 100ah battery is at 50% (worst case), is it going to try and draw all 50 amps at once when connected to a power source?
The resistance of the wire and the internal resistance of the battery will determine how much of the alternator's potential is actually allowed to flow through the battery.
So, with BigAss wire, it could easily be possible to see 50a or more flowing through the battery - initially. But as the voltage of the battery rises, so does its resistance, and the amount of current (amps) slowly gets more and more choked off.
Would a resistor on the power box (between the battery and the 12v power coming in) draw the current down to a level that would keep from popping the fuse?
Yes, but it could also lower the voltage, which could make the battery end up taking a lot longer to get full.
Besides, the battery itself is one giant resistor.
Even 10a would be sufficient for what I'm trying to do. 10a constant draw ought not to blow my 15a fuse would it?
It won't be constant. No matter what, with a lead-acid battery, as its voltage rises (assuming you start at 50% and not 0%) its resistance rises and amps flowing goes down.
And when it's at 50%, its resistance is just about at its lowest point - allowing the most current to flow.
But if you find a way to limit the current to 10a, then no, you won't blow a 15a fuse.
And it's possible that whatever battery you buy, together with whatever wire you use, might achieve that naturally.
Or is the better alternative, as you say, to put an inverter on the vehicle side and use a 120vAC charger? In that case, what wattage of inverter would I need? Maybe something like this?
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http://products.batterytender.com/A...R-5A-Power-Tender-Series-High-Efficiency.html
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Advertised as a 5a charger, my only question is, what wattage of an inverter would I need? 5a x 12v = 60w which would mean I could connect it to a basic 150w inverter like this one:
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https://www.walmart.com/ip/12V-DC-t...00002364&wl14=12v power inverter 150w&veh=sem
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But that can't be right, can it? 60w is a light bulb, surely it would take a bigger inverter to run this wouldn't it?
Dunno. At work and gotta run. I'll come back to inverter + battery charger later.